JAMB UTME - Physics - 2004 | Green Bridge CBT

Question 1 Report

When left in a freezer, a bottle full of water cracks on freezing into ice because of the

increase in the volume of water

contraction of the bottle

expansion of the bottle

decrease in the volume of water

Answer Details

Read lesson note on Fluid At Rest (WAEC)

Read lesson note on Temperature And Its Measurement (JAMB)

Fluid At Rest

Temperature And Its Measurement

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Question 2 Report

A man exerts a pressure of 2.8 x 103Nm-2 on the ground and has 4 x 10-2m2 of his feet in contact with the ground. The weight of the man is

102N

70N

140N

112N

Answer Details

The pressure exerted by a person is defined as the force per unit area, where force is the weight of the person and area is the surface area of the contact between the person and the ground. Here, the pressure exerted by the man is given as 2.8 x 10^3 Nm^-2 and the surface area of his feet in contact with the ground is 4 x 10^-2 m^2. To find the weight of the man, we can use the formula: pressure = force/area Rearranging the formula, we get: force = pressure x area Substituting the given values, we get: force = (2.8 x 10^3 Nm^-2) x (4 x 10^-2 m^2) = 112 N Therefore, the weight of the man is 112N. Hence, the answer is 112N.

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Pressure

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Question 3 Report

Transverse waves can be distinguished from longitudinal waves using the characteristic of

diffraction

refraction

polarization

reflection

Answer Details

Transverse waves can be distinguished from longitudinal waves using the characteristic of polarization. Polarization is a property of transverse waves, which describes the direction of the vibrations of the wave in relation to the direction of wave propagation. In a transverse wave, the vibrations are perpendicular to the direction of wave propagation, whereas in a longitudinal wave, the vibrations are parallel to the direction of wave propagation. Therefore, polarization is a key characteristic that distinguishes transverse waves from longitudinal waves. Diffraction, refraction, and reflection are properties that apply to both transverse and longitudinal waves.

Read lesson note on Sound Waves (WAEC)

Read lesson note on Properties Of Waves: Reflection, Refraction, Diffraction (WAEC)

Read lesson note on Types Of Waves (WAEC)

Sound Waves

Properties Of Waves: Reflection, Refraction, Diffraction

Types Of Waves

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Question 4 Report

Given three capacitors 0.3μF, 0.5μF and 0.2μF, the joint capacitance when arranged to give minimum capacitance is

0.1μF

0.3μF

1.0μF

0.5μF

Answer Details

When capacitors are arranged in parallel, the equivalent capacitance is given by the sum of individual capacitances. When capacitors are arranged in series, the inverse of the equivalent capacitance is given by the sum of the inverses of individual capacitances. To obtain the minimum capacitance, the capacitors should be arranged in series. Therefore, the equivalent capacitance will be: 1/C = 1/C1 + 1/C2 + 1/C3 Substituting the given values, we get: 1/C = 1/0.3μF + 1/0.5μF + 1/0.2μF Solving the above equation, we get: C = 0.086μF Therefore, the equivalent capacitance is approximately 0.1μF, which is the first option.

Read lesson note on Capacitors (JAMB)

Read lesson note on Simple A.C Circuits (JAMB)

Capacitors

Simple A.C Circuits

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Question 5 Report

What happens to the rays in a parallel beam of light?

They diverge as they travel

they intersect

They converge as they travel

They meet at infinity.

Answer Details

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Light Energy

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Question 6 Report

In a hydraulic press , a force of 40N is applied on the effort piston of area 0.4m2. If the force exerted on the load piston is 400N, the area of the large piston is

4m2

8m2

2m2

1m2

Answer Details

Pressure developed in the effort piston = F/a
∴F/a = 40/0.4 = 400/4 = 100Nm2
this pressure is transmitted to the larger piston of area A; => P = F/A
∴ 100 = 400/A
=> A = 400/100 = 4m2

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Measurements And Units

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Question 7 Report

The instrument used for securing a large number of similar charges by induction is called

electrophorus

capacitor

proof-plane

electroscope

Answer Details

The instrument used for securing a large number of similar charges by induction is called an electrophorus. An electrophorus consists of two parts: a metal plate and a non-conducting plate, usually made of plastic. The metal plate is charged by rubbing it with a fur or other material, which causes a buildup of negative charge on the plate. When the non-conducting plate is placed on top of the metal plate, the negative charge on the metal plate induces a positive charge on the top of the non-conducting plate. This process can be repeated multiple times, resulting in a large number of charges that can be used for various experiments or applications.

Read lesson note on Electrostatics (JAMB)

Electrostatics

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Question 8 Report

A 50W electric heater is used to heat a metal block of mass 5kg. If in 10 minutes a temperature rise of 12oC is achieved, the specific heat capacity of the metal is

400 J kg-1K-1

500 J kg-1K-1

390 J kg-1K-1

130 J kg-1K-1

Answer Details

The specific heat capacity of a substance is the amount of energy required to raise the temperature of 1 kilogram of that substance by 1 degree Celsius. In this problem, we have a 50W electric heater that is used to heat a metal block of mass 5kg. We are also given that the temperature of the block increases by 12°C in 10 minutes. To find the specific heat capacity of the metal, we can use the formula: Q = mcΔT where Q is the amount of heat energy transferred, m is the mass of the metal block, c is the specific heat capacity of the metal, and ΔT is the change in temperature of the metal block. We know that the electric heater is supplying 50J of heat energy per second (since 1W = 1J/s), and the heater is operating for 10 minutes, or 600 seconds. Therefore, the total amount of heat energy supplied to the metal block is: Q = (50 J/s) x (600 s) = 30,000 J We also know that the mass of the metal block is 5kg, and the temperature of the block increases by 12°C. Therefore, we can rearrange the formula above to solve for the specific heat capacity: c = Q/(mΔT) = 30,000 J/(5 kg x 12°C) = 500 J/(kg·°C) Therefore, the specific heat capacity of the metal is 500 J/(kg·°C). So, the correct option is: 500 J kg-1K-1.

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Heat Energy

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Question 9 Report

The pitch of a sound note depends on

timbre

frequency

harmonics

quality

Answer Details

The pitch of a sound note depends on its frequency. Pitch refers to the perceived highness or lowness of a sound, and is determined by the frequency of the sound wave. The higher the frequency, the higher the pitch of the sound. Therefore, among the given options, the correct answer is "frequency". Timbre, harmonics, and quality also affect the perceived sound, but they do not directly determine the pitch of the sound.

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Read lesson note on Sound Waves (WAEC)

Current Electricity

Sound Waves

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Question 10 Report

Metal rods of length 20m each are laid end to end to form a bridge at 25oC. What gap will be provided between consecutive rails for the bridge to withstand 75oC?

[Linear expansivity of the material = 2.0 x 10-5K-1]

0.20m

0.22m

0.25m

0.02m

Answer Details

The problem involves finding the gap to be provided between the consecutive metal rods, which are laid end to end to form a bridge at 25°C, so that the bridge can withstand a temperature of 75°C. The linear expansivity of the material is given as 2.0 x 10^-5 K^-1. When the temperature of a material increases, it expands in length. The amount of expansion is given by the coefficient of linear expansion, which is the increase in length per unit length per unit increase in temperature. Let x be the gap to be provided between consecutive rails at 25°C. When the temperature increases to 75°C, each metal rod will expand by a length of (20m x 2.0 x 10^-5 K^-1 x 50K) = 0.02m. Therefore, the total increase in length for two consecutive rods and the gap between them will be 0.04m. To ensure that the bridge can withstand the increased temperature, the gap between the consecutive rails should be equal to the total increase in length, which is 0.04m. Since there are two gaps between three rods, the gap to be provided between consecutive rails is half of 0.04m, which is equal to 0.02m. Therefore, the answer is option D, 0.02m.

Read lesson note on Thermal Expansion (JAMB)

Thermal Expansion

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Question 11 Report

The phase difference between waves P and q in the diagram above is

2π

π/4

π/2

Answer Details

From the given diagram, it can be observed that wave P reaches its maximum amplitude at time t=0, whereas wave Q reaches its maximum amplitude at time t=T/4. Since the time difference between the maximum points of the two waves is T/4, where T is the time period of the waves, we can say that the phase difference between waves P and Q is π/2 or 90 degrees. Therefore, the correct option is: π/2.

Read lesson note on Sound Waves (WAEC)

Sound Waves

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Question 12 Report

For semi conductor to have negative temperature coefficient of resistance implies that

their resistance decrease with temperature

The resistance increase with temperature

their resistance is constantly changing with temperature

they have electrons and holes at high temperature

Answer Details

Temperature coefficient of resistance is given by

α =	Increase in resistance per oC rise in temp.
	__resistance at 0oC

And for metals where resistance increase with temperature rise, temperature coefficient of resistance is positive; on the other hand in semi conductors, where resistance decrease with temperature rise, temperature coefficient of resistance is negative.

Read lesson note on Electrostatics (JAMB)

Electrostatics

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Question 13 Report

I. Jet propelled aircraft

II. Rocket propulsion

III. The recoil of a gun

IV. A person walking

Which of the above is based on Newton's third law of motion

I and II only

I, II, III, and IV only

I and III only

I, II and III only

Answer Details

Newton's third law of motion states that for every action, there is an equal and opposite reaction. Among the given options, the following satisfy this law: - III. The recoil of a gun: The action is the explosion of gas in the gunpowder which creates a forward force on the bullet and an equal and opposite force on the gun, causing the gun to recoil. - I. Jet propelled aircraft: The action is the expulsion of gases from the back of the jet engine, which creates a forward force on the aircraft, and an equal and opposite force in the opposite direction. - II. Rocket propulsion: The action is the ejection of exhaust gases from the nozzle of the rocket, which creates a forward force on the rocket, and an equal and opposite force in the opposite direction. Therefore, the answer is: I, II, and III only.

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Newton’s Laws Of Motion

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Question 14 Report

Which of the following is an electrolyte?

Paraffin

Sugar solution

Grape fruit

Alcohol

Answer Details

Read lesson note on Electrostatics (JAMB)

Electrostatics

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Question 15 Report

The difference between X-rays and gamma rays is that

x-rays are more penetrating than gamma rays

x-rays are electromagnetic radiations while gamma rays are negatively charged radiation

x-rays have higher frequencies than gamma rays

x-rays arise from energy changes in the electronic structure of atoms while gamma rays come from the nucleus

Answer Details

Read lesson note on Electromagnetic Waves: Types Of Radiation In Electromagnetic Spectrum (WAEC)

Read lesson note on Electromagnetic Field (Part 2) (WAEC)

Electromagnetic Waves: Types Of Radiation In Electromagnetic Spectrum

Electromagnetic Field (Part 2)

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Question 16 Report

A 100kg box is pushed along a road with force of 500N. If the box moves with a uniform velocity, the coefficient of friction between the box and the road is

0.4

1.0

0.8

0.5

Answer Details

To find the coefficient of friction between the box and the road, we need to use the formula for frictional force, which is given by: f_friction = coefficient of friction x normal force. Since the box is moving with a uniform velocity, we know that the net force acting on the box is zero. The force pushing the box forward is balanced by the force of friction acting in the opposite direction. Therefore, we can set up an equation to find the force of friction acting on the box: f_push - f_friction = 0 where f_push is the force pushing the box forward, and f_friction is the force of friction acting in the opposite direction. Substituting the values given in the problem, we get: 500N - f_friction = 0 Solving for f_friction, we get: f_friction = 500N Now, we can use the formula for frictional force to find the coefficient of friction: f_friction = coefficient of friction x normal force The normal force is the force exerted by the road on the box, which is equal to the weight of the box (since the box is not accelerating): normal force = weight of box = mg = 100kg x 9.8 m/s^2 = 980N Substituting this value and the value we found for the force of friction into the formula for frictional force, we get: 500N = coefficient of friction x 980N Solving for the coefficient of friction, we get: coefficient of friction = 500N / 980N = 0.51 Therefore, the coefficient of friction between the box and the road is approximately 0.5, which is the fourth option.

Read lesson note on Scalars And Vectors (JAMB)

Read lesson note on Work, Energy And Power (WAEC)

Scalars And Vectors

Work, Energy And Power

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Question 17 Report

In a reverse biased junction diode, current flows in by

positive holes alone

majority carriers

electron alone

minority carriers

Answer Details

In a reverse biased junction diode, current flows in by minority carriers. When a junction diode is reverse biased, the P-type region is connected to the negative terminal of the battery and the N-type region is connected to the positive terminal. In this condition, the holes in the P-type region and the electrons in the N-type region are both moving away from the junction, creating a depletion region with very few charge carriers. However, due to the presence of a small number of impurities, there are still some charge carriers present in this region, known as minority carriers. These minority carriers can contribute to the reverse current that flows through the diode when a voltage is applied in the reverse direction. Therefore, the correct option is "minority carriers".

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Electrostatics

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Question 18 Report

What types of mirror are capable of producing parallel beams of light such as those arising from the headlamps of a car?

Parabolic mirrors

Plane mirrors

Cylindrical mirrors

Spherical mirrors

Answer Details

Parabolic mirrors are capable of producing parallel beams of light such as those arising from the headlamps of a car. This is because parabolic mirrors have a unique shape that can reflect light rays that come in parallel to the axis of the mirror, back out as parallel beams. Plane mirrors, cylindrical mirrors, and spherical mirrors do not have this property, and so they cannot produce parallel beams of light in the same way that parabolic mirrors can.

Read lesson note on Reflection Of Light At Plane And Curved Surfaces (JAMB)

Reflection Of Light At Plane And Curved Surfaces

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Question 19 Report

A moving coil galvanometer has a full-scale deflection of 3A equivalent to 30o deflection. The sensitivity of the instrument is

33.0

0.1

90.0

10.0

Answer Details

The sensitivity of a moving coil galvanometer is the deflection produced per unit current passing through it. In this question, we are given that the full-scale deflection of the galvanometer is 30° which is equivalent to 3A. So, the sensitivity of the galvanometer can be calculated as follows: Sensitivity = (Full-scale deflection) / (Current producing it) Sensitivity = 30° / 3A = 10°/A Therefore, the sensitivity of the instrument is 10.0. Option (D) is the correct answer.

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Current Electricity

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Question 20 Report

Electrical appliances at home are normally earthed so that

the appliances are maintained at a lower p.d than the earth

both the a.c and d.c sources can be used

a person touching the appliances is safe from electric shock

the appliances are maintained at a higher p.d than the earth

Answer Details

Electrical appliances at home are normally earthed so that a person touching the appliances is safe from electric shock. When an appliance is not earthed and there is a fault, it can become live and carry an electric current. If a person touches the live appliance, the current can flow through their body to the earth, causing electric shock. However, when an appliance is earthed, any fault current flows to the earth instead of flowing through the body of the person touching the appliance, making it safer.

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Question 21 Report

Tea pots are often silver-coated to prevent heat loss by

conduction only

convention only

convection and conduction

radiation only

Answer Details

Tea pots are often silver-coated to prevent heat loss by radiation only. Silver is a good reflector of heat, and the shiny surface of the silver-coated tea pot reflects the heat back into the pot, preventing it from radiating out into the surrounding environment.

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Heat Transfer

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Question 22 Report

Calculate the angle of minimum deviation for a ray which is refracted through an equiangular prism of refractive index 1.4

600

290

990

900

Answer Details

The formula for the angle of minimum deviation for an equiangular prism is given as: $$ \delta_{\text{min}} = \frac{A}{2} + \text{arcsin}\left(\frac{n}{\sqrt{2}}\sin\frac{A}{2}\right) - 90^\circ $$ where $A$ is the angle of the prism and $n$ is the refractive index of the prism. For an equiangular prism, $A = 60^\circ$. Substituting $A$ and $n=1.4$ into the formula, we get: $$ \delta_{\text{min}} = \frac{60^\circ}{2} + \text{arcsin}\left(\frac{1.4}{\sqrt{2}}\sin\frac{60^\circ}{2}\right) - 90^\circ \approx 29^\circ $$ Therefore, the angle of minimum deviation for a ray refracted through an equiangular prism of refractive index 1.4 is approximately 29 degrees. Thus, the correct option is 290.

Read lesson note on Refraction Of Light Through Plane And Curved Surfaces (JAMB)

Refraction Of Light Through Plane And Curved Surfaces

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Question 23 Report

A body of mass 4kg is acted on by a constant force of 12N for 3 seconds. The kinetic energy gained by the body at the end of the time is

144J

162J

81J

72J

Answer Details

The kinetic energy gained by a body is equal to the work done on it by a force, as given by the formula: Kinetic energy gained = work done = force x distance In this problem, the force acting on the body is constant at 12N, and it acts for a time of 3 seconds. We can find the distance moved by the body using the formula for distance travelled by an object under constant acceleration: Distance = (1/2) x acceleration x time^2 Since the force on the body is constant, we can use Newton's second law to find its acceleration: Force = mass x acceleration Acceleration = Force / mass = 12N / 4kg = 3 m/s^2 Using this acceleration, we can find the distance travelled by the body: Distance = (1/2) x 3 m/s^2 x (3 s)^2 = 13.5 m Now, we can use the formula for work done to find the kinetic energy gained by the body: Work done = force x distance = 12N x 13.5m = 162 J Therefore, the correct answer is 162J.

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Work, Energy And Power

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Question 24 Report

A steady current of 2A flows in a coil of emf 12V for 0.4s. A back emf of 3V was induced during this period. The stored energy in the loop that can be utilized is

9.6J

2.4J

12.0J

7.2J

Answer Details

Energy stored = Ivt = current x back e.m.f x time
= 2 x 3 x 0.4
= 2.4J

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Current Electricity

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Question 25 Report

As the pressure of a fluid increases, its viscosity

decreases

increases

increases then decreases

remains constant

Answer Details

As the pressure of a fluid increases, its viscosity increases. Viscosity is the measure of a fluid's resistance to flow. When pressure is increased, the molecules in the fluid come closer together, leading to stronger intermolecular forces and increased friction between them. This results in an increase in viscosity, making it more difficult for the fluid to flow. Therefore, is correct.

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Pressure

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Question 26 Report

The diagram above shows forces 4N, 6N, 10N and 8N which act at a point O in the directions indicated. the net horizontal force is

13N

17N

√3N

7√3N

Answer Details

Component of 8N along the horizontal = 8 cos 60o = 8 x 0.5
= 4N
Similarity Component of 6N along the horizontal = 6 cos 60o = 3N
∴ Total force towards the right = 10 + 4 + 3
= 17N
Again total force toward the left = 4N
∴ Net horizontal force (towards the right) = 17-4
= 13N

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Question 27 Report

If the angle between two vector P and Q is Oo, the vectors are said to

intersect at the angle 45o

intersect at the angle 60o

be parallel

be perpendicular

Answer Details

When the angle between two vectors P and Q is 0, it means that they are pointing in the same direction, i.e., they are parallel. Therefore, the correct option is "be parallel."

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Scalars And Vectors

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Question 28 Report

A radioisotope has a decay constant of 10-7s-1. The average life of the radioisotope is

1.00 x 107s

6.93 x 108s

1.00 x 10-7s

6.93 x 107s

Answer Details

Average life / Half life (Tl/2) = ln2/λ = 0.693/10-7
= 0.693 x 107
= 6.93 x 108

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Position, Distance And Displacement

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Question 29 Report

A cell whose internal resistance is 0.5Ω delivers a current of 4A to an external resistor,The loss voltage of the cell is

1.250V

2.000V

8.000V

0.125V

Answer Details

When a cell delivers a current to an external resistor, there is a drop in voltage across the internal resistance of the cell due to the resistance of the cell. This is known as the "loss voltage" of the cell. We can use Ohm's law to calculate the loss voltage of the cell. Ohm's law states that V = IR, where V is voltage, I is current, and R is resistance. In this case, the internal resistance of the cell is given as 0.5Ω and the current delivered by the cell is 4A. Thus, the loss voltage of the cell is: V = IR = (4A)(0.5Ω) = 2V Therefore, the answer is 2.000V.

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Electric Cells

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Question 30 Report

The energy stored in an inductor of inductance 5mH when a current of 6A flows through it is

9.0 x 10-3J

9.0 x 10-2J

1.4 x 10-2J

1.8 x 10-3J

Answer Details

The energy stored in an inductor can be calculated using the formula: E = 0.5 * L * I^2 where E is the energy stored, L is the inductance, and I is the current flowing through the inductor. Substituting the given values, we get: E = 0.5 * 5mH * (6A)^2 First, we need to convert millihenry (mH) to henry (H): 1mH = 0.001H Therefore, E = 0.5 * 0.005H * (6A)^2 Simplifying, E = 0.09J So the energy stored in the inductor is 0.09J. Therefore, the correct option is: 9.0 x 10-2J.

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Capacitors

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Question 31 Report

The particle and wave nature of matter are demonstrated in the equation

λ = hc/E

λ = h/P

λ = c/f

λ = 2 d sin θ

Answer Details

The equation that demonstrates the particle and wave nature of matter is the second option: λ = h/P. This equation is known as the de Broglie wavelength equation, and it relates the wavelength of a particle to its momentum. This equation implies that particles, like waves, can have a wavelength and frequency, which is a property of waves. In other words, it shows that particles have a dual nature, they can behave as both particles and waves. The first option, λ = hc/E, is the equation for the energy of a photon, which demonstrates the wave nature of light. The third option, λ = c/f, is the equation for the wavelength of light, which also demonstrates the wave nature of light. The fourth option, λ = 2dsinθ, is the equation for the diffraction of waves, which is also a property of waves.

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Structure Of The Atom (Nigeria Only)

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Question 32 Report

I. Wavelength

II. Medium of propagation

III. Wave velocity

IV. Frequency

V. Energy

Which of the above are used for characterizing waves?

I, II and V

I and IV

I, III and IV

III, IV and V

Answer Details

Read lesson note on Properties Of Waves: Reflection, Refraction, Diffraction (WAEC)

Properties Of Waves: Reflection, Refraction, Diffraction

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Question 33 Report

An a.c circuit of e.m.f 12V has a resistor of resistance 8Ω connected in series to an inductor of inductive reactance 16Ω and a capacitor capacitive reactance 10Ω. The current flow in the circuit is

1.4A

1.2A

12.0A

14.0A

Answer Details

In this AC circuit, there is a resistor, an inductor, and a capacitor connected in series. The current flow in the circuit is given by the equation I = V/Z, where V is the voltage, and Z is the impedance of the circuit. The impedance of a series circuit is given by the equation Z = sqrt(R^2 + (Xl - Xc)^2), where R is the resistance, Xl is the inductive reactance, and Xc is the capacitive reactance. Substituting the given values, we have: Z = sqrt(8^2 + (16 - 10)^2) Z = sqrt(64 + 36) Z = sqrt(100) Z = 10Ω The voltage is given as 12V. Therefore, the current flow in the circuit is: I = V/Z I = 12/10 I = 1.2A Hence, the answer is 1.2A.

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Question 34 Report

If u is the object distance and v the image distance, which of the following expressions gives the linear magnification produced by a convex lens of focal length f?

u/f - f

u/v + f

v/f + 1

v/f - 1

Answer Details

Magnification, M = v/u = v (1/u)
And for the Lens formula 1/u + 1/v = 1/f
=>1/u = 1/f - 1/v
∴M = V(1/u)
= V(1/f - 1/v) = v/f - v/v = v/f - 1
∴M = v/f - 1

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Structure Of The Atom (Nigeria Only)

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Question 35 Report

In a tuned radio receiver R, L, C series circuit for resonance, the inductive and capacitive reactance XL and XC respectively are related as

XL = XC

XL = 1/2XC

XL = 1/XC

XL = 2XC

Answer Details

In a tuned radio receiver R, L, C series circuit for resonance, the inductive and capacitive reactance X_L and X_C respectively are related as X_L = 1/(2πfC) and X_C = 1/(2πfL), where f is the frequency of the applied voltage. Therefore, substituting X_C into X_L, we get X_L = X_C. Hence, the correct answer is X_L = X_C.

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Question 36 Report

The earth is four times the size of the moon and the acceleration due to gravity on the earth is 80 times that on the moon. The ratio of the mass of the moon to that of the earth is

1:80

1:320

1:1280

1:4

Answer Details

NOTE: Firstly, it should be noted that the mass, as well as the weight of a body is independent of its size.
∴ Let the weight of the moon = Mm x gm
weight of the earth = Me x ge
But ge = 80gm
∴ weight of the earth = Me x 80gm
=> weight of the moon / weight of the earth = Mm x gm / Me x 80gm
thus Mm/Me ∝ gm/80gm ∝ 1/80
=> Mm:Me ∝ 1:80

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Read lesson note on Gravitational Field (JAMB)

Work, Energy & Power

Gravitational Field

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Question 37 Report

The change in volume when 450kg of ice is completely melted is

[density of ice = 900 kgm-3, density of water = 100 kgm-3]

0.50m3

0.45m3

0.05m3

4.50m3

Answer Details

Vol. of ice = M/?D = 450/900 = 0.500m3
vol. of water = M/D" = 450/1000 = 0.450m3
∴ Difference in vol. = 0.500 - 0.450
= 0.05m3

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Quantity Of Heat

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Question 38 Report

X rays can be used in the study of crystal structure because they

have a very long-reaching wavelength

have extremely short wavelength

are invisible

are very fast

Answer Details

X-rays can be used in the study of crystal structure because they have an extremely short wavelength. This allows them to diffract off the atoms in the crystal lattice, producing a unique pattern that can be used to determine the arrangement of atoms within the crystal. The short wavelength of X-rays allows them to interact with the closely spaced atoms in the crystal, giving rise to the diffraction pattern. The other options are incorrect: X-rays are not long-reaching, they are not invisible (they can be detected using photographic film or electronic detectors), and their speed is not a factor in their usefulness for crystallography.

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Electromagnetic Field (Part 2)

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Question 39 Report

A generator manufacturing company was contracted to produce an a.c dynamo but inadvertently produced a d.c dynamo. To correct this error, the

armature coil should be made of silver

commutator should be replaced with slip ring

commutator should be replaced with split rings

armature coil should be made of aluminium

Answer Details

An a.c dynamo and a d.c dynamo are two different types of generators that produce different types of currents. An a.c dynamo produces alternating current while a d.c dynamo produces direct current. To correct the error of producing a d.c dynamo instead of an a.c dynamo, the commutator should be replaced with slip rings. The commutator is a device that converts the alternating current produced by the dynamo into direct current. Since the dynamo was inadvertently made to produce direct current, there is no need for a commutator, and it should be replaced with slip rings which allow the output to be collected as alternating current.

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Capacitors

Simple A.C. Circuits

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Question 40 Report

The refractive index of the medium M in the diagram above is

1/√3

2√3

√3

2/√3

Answer Details

In the diagram given, the incident ray AO is perpendicular to the surface AB. Therefore, it will pass straight through without deviation. When it reaches the surface BC, it will refract according to Snell's law. We can write: sin(i)/sin(r) = n where i is the angle of incidence, r is the angle of refraction, and n is the refractive index of the medium. Since the incident ray is perpendicular to AB, i = 0. We can then simplify the equation to: sin(r) = 0 This means that the refracted ray is parallel to the surface BC. When it reaches the surface CD, it will once again refract according to Snell's law. We can write: sin(i)/sin(r) = n where i is the angle of incidence and r is the angle of refraction. The incident angle i is equal to the angle of reflection, which is 60 degrees in this case. We can then simplify the equation to: sin(60)/sin(r) = n Solving for n, we get: n = sin(60)/sin(r) The angle of minimum deviation occurs when the refracted ray is symmetric with respect to the incident ray. In other words, the angles of incidence and refraction are equal. Since the incident angle is 60 degrees, the angle of refraction at CD is also 60 degrees. Therefore, we can substitute r = 60 degrees into the equation above to get: n = sin(60)/sin(60) = 1 The refractive index of the medium M is therefore 1. Answer option (2√3) is incorrect because it is greater than 1, and answer options (1/√3) and (2/√3) are incorrect because they are less than 1. The correct answer is option ( √3).

Read lesson note on Refraction Of Light Through Plane And Curved Surfaces (JAMB)

Read lesson note on Properties Of Waves: Reflection, Refraction, Diffraction (WAEC)

Refraction Of Light Through Plane And Curved Surfaces

Properties Of Waves: Reflection, Refraction, Diffraction

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Question 41 Report

A machine whose efficiency is 60% has a velocity ratio of 5. If a force of 500N is applied to lift a load P, what is the magnitude of P?

1500N

500N

4166N

750N

Answer Details

efficiency = (M.A / V.R) x 100/1 =>60/100 = M.A/5
∴M.A = (60 X 5) / 100 = 3
But M.A = Load/Effort; => 3 = Load/500
∴Load = 500 x 3
= 1500N

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Simple Machines

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Question 42 Report

Flourescent tubes produces light by the

excitation of gas molecules

conduction of solar energy

refraction of light by gas molecules

thermal agitation of electron in the tubes

Answer Details

Fluorescent tubes produce light by the excitation of gas molecules. Fluorescent tubes have a gas mixture containing low-pressure mercury vapor and noble gases like argon, neon, or krypton. The gas inside the tube gets excited by electricity and emits ultraviolet (UV) light. The UV light excites the phosphor coating on the inside of the glass tube, causing it to emit visible light. The gas molecules act as a medium for the transfer of energy between the electrical source and the phosphor coating.

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Question 43 Report

To protect a material from the influnce of an external magnetic field, the materials should be kept

square steel ring

triangular zinc ring

soft iron ring

loop of copper wire

Answer Details

In order to protect a material from the influence of an external magnetic field, the material is placed in a soft iron ring, usually referred to as magnetic screening.

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Magnets And Magnetic Fields

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Question 44 Report

A ray of light makes an angle of 35o with a plane mirror. What is the angle of reflection?

35o

55o

70o

65o

Answer Details

35o =35o = 70o
180 - 70 = 110
110/2 = 55o

Read lesson note on Reflection Of Light At Plane And Curved Surfaces (JAMB)

Reflection Of Light At Plane And Curved Surfaces

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Question 45 Report

If 16mA of current flows through a conductor in one second, the number of electron transported per seconds is

[1 electronic charge = 1.6 x 10-19C]

1.00 x 1020

2.56 x 10-18

2.56 x -17

1.00 x 1017

Answer Details

Current (I) = q/t → q = i x t
= 16 x 10-3 x 1
= 1.6 x 10-2C
But 1.6 x 10-19C = I electronic charge
1 coulomb = 1 / (1.6x10-19)
∴ 1.6 x 10-2 coulombs = 1 / (1.6x10-19) x 1.6x10-2 / 1
= 1.0 x 10-2 x 1019
= 1.0 x 1017

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Current Electricity

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Question 46 Report

If a force of 50N stretches a wire from 20m to 20.01m, what is the amount of force required to stretch the same material from 20m to 20.05m?

250N

200N

100N

50N

Answer Details

To solve this problem, we need to use Hooke's law, which states that the force required to stretch or compress a spring is directly proportional to the extension or compression of the spring. We can represent this law as: F = kx where F is the force applied, x is the extension or compression of the spring, and k is a constant known as the spring constant. We can use this formula to solve the problem by first finding the spring constant of the wire. To do this, we can use the given force and extension: 50N = k(20.01m - 20m) k = 50N / 0.01m k = 5000 N/m Now we can use this spring constant to find the force required to stretch the wire from 20m to 20.05m: F = kx F = 5000 N/m * (20.05m - 20m) F = 250N Therefore, the amount of force required to stretch the wire from 20m to 20.05m is 250N. Answer: 250N.

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Elasticity

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Question 47 Report

The binding energy of helium	4	He is
	2

[atomic mass of proton = 1.00783U,

Atomic mass of neutron = 1.00867U]

4.033U

2.017U

0.033U

0.330U

Answer Details

The binding energy of helium refers to the amount of energy required to separate the two protons and two neutrons in the helium nucleus. The table provided shows the atomic masses of helium with two different numbers of neutrons. By subtracting the atomic mass of the helium nucleus with two neutrons from the one with four neutrons, we can find the mass defect, which is the mass that is converted to energy in the process of binding the nucleus. Using Einstein's famous equation E=mc², we can calculate the binding energy from the mass defect. The mass defect can be calculated as: mass defect = (atomic mass of helium with 2 neutrons) + 2 × (atomic mass of a proton) + 2 × (atomic mass of a neutron) - atomic mass of helium with 4 neutrons Substituting the given values, we get: mass defect = 2.014101u + 2 × 1.00783u + 2 × 1.00867u - 4.002603u mass defect = 0.030379u Using E=mc², we can find the binding energy, where c is the speed of light in a vacuum (299,792,458 m/s): binding energy = mass defect × c² binding energy = 0.030379u × (299,792,458 m/s)² binding energy ≈ 2.73 × 10⁻¹² J Therefore, the answer is 0.033U.

Read lesson note on Structure Of The Atom (Nigeria Only) (WAEC)

Structure Of The Atom (Nigeria Only)

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Question 48 Report

In which of the following material media will sound travel fastest?

oil

metal

gas

water

Answer Details

Sound travels fastest through solids, such as metals, because the particles are closest together, making it easier for the sound wave to propagate. Therefore, the option that best answers the question is "metal".

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Read lesson note on Rectilinear Acceleration (WAEC)

Read lesson note on Reflection Of Light At Plane And Curved Surfaces (JAMB)

Read lesson note on Simple A.C Circuits (JAMB)

Current Electricity

Rectilinear Acceleration

Reflection Of Light At Plane And Curved Surfaces

Simple A.C Circuits

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Question 49 Report

A person can focus an object only when it lies within 200cm from him. Which spectacles should be used to increase his maximum distance of distinct vision infinity

Convex lens

Binoculars

Concave lens

Plane glasses

Answer Details

A person who can only focus on an object within 200cm is nearsighted or myopic. To increase their maximum distance of distinct vision to infinity, they would need a lens that can correct their nearsightedness. A convex lens is used to correct nearsightedness by diverging the light rays before they enter the eye, allowing for proper focus on distant objects. Therefore, the spectacles that should be used to increase the person's maximum distance of distinct vision to infinity is a convex lens.

Read lesson note on Structure Of The Atom (Nigeria Only) (WAEC)

Structure Of The Atom (Nigeria Only)

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Question 50 Report

In the diagram above, the ratio of he electric power dissipated in the 6Ω and the 3Ω resistor respectively is

2:1

2:2

1:3

1:2

Answer Details

To solve the problem, we can use the formula for electric power, which is P = VI, where P is power, V is voltage, and I is current. Using Ohm's law, we can also write V = IR, where R is resistance. First, we need to find the current flowing through the circuit. Since the resistors are in parallel, the voltage across them is the same, and we can use Ohm's law to find the current through each resistor. For the 6Ω resistor, V = IR = (12V)/(6Ω) = 2A For the 3Ω resistor, V = IR = (12V)/(3Ω) = 4A Now, we can calculate the power dissipated in each resistor using the formula P = VI. For the 6Ω resistor, P = VI = (2A)(12V) = 24W For the 3Ω resistor, P = VI = (4A)(12V) = 48W The ratio of the power dissipated in the 6Ω resistor to that in the 3Ω resistor is 24W:48W, which simplifies to 1:2. Therefore, the answer is option (D) 1:2.

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Electrostatics

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