JAMB UTME - Chemistry - 2007 | Green Bridge CBT

Question 1 Report

What weight of NaCl is needed to make 2.0 dm3 of a 1.5M solution?

[Na = 23, Cl = 35.5]

116 g

175 g Correct answer

87 g

58 g

Answer Details

To find the weight of NaCl required, we need to use the formula: moles = concentration x volume First, we need to find the number of moles of NaCl required to make 2.0 dm^3 of a 1.5 M solution: moles = concentration x volume moles = 1.5 mol/dm^3 x 2.0 dm^3 moles = 3.0 mol Next, we can use the molar mass of NaCl (58.44 g/mol) to convert moles to grams: grams = moles x molar mass grams = 3.0 mol x 58.44 g/mol grams = 175.32 g Therefore, the weight of NaCl required to make 2.0 dm^3 of a 1.5 M solution is approximately 175 g. So, the correct answer is.

Read lesson note on Stoichiometry And Chemical Reactions (WAEC)






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