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Question 1 Report
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Question 6 Report
For what values of F and ? will the forces shown in the diagram below be in equilibrium.
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Question 9 Report
A force of 5N acts at a point Y on a rod XYZ as shown in this diagram. If XYZ is 2m, what is the moment of the force about point X?
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Question 17 Report
A lens of focal length 15cm forms on erect image which is three times the size of the object. The distance between the object and the image is ___.
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Question 20 Report
An object moves in a circular path of radius 0.5m with a speed of \(1ms^{-1}\). What is its angular velocity?
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Question 21 Report
A ball of mass 5.0kg hits a smooth vertical wall normally with a speed of \(2\text{ms}^{-1}\). Determine the magnitude of the resulting impulse
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Question 22 Report
In the diagram given if the atmospheric pressure is 760mm, the pressure in the chamber G Is
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Question 27 Report
A boy receives the echo of his clap reflected by a nearby hill 0.8s later. If the speed of sound in air is 3.40ms\(^{-1}\), how far is he from the hill?
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Question 29 Report
A solid cube of side 50cm and mass 75kg floats in a liquid with \( \frac{1}{3} \) of its height above the liquid surface. The relative density of the liquid is?
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Question 30 Report
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Weight of water displaced = upthrust = 30 - 21 = 9N
Mass of water displaced = 910
= 0.9kg
Volume of object = 9 × 10−4
m3
= (9 × 10−4
) (1.4 ×103)
= 1.26kg = 12N
30 - 12.6 = 17.4N
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Question 33 Report
Calculate the effective capacitance of the circuit in the diagram given
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Question 34 Report
Which of the following statements are TRUE of isotopes?
I. Isotopes of an element have the same chemical properties because they have the same number of electrons
II. Isotopes of elements are normally separated using physical properties
III. Isotopes of an element have the same number of protons in their nuclei
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Question 35 Report
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Question 38 Report
Which of the following diagrams represents correctly an n-p-n transistor?
i.
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Question 39 Report
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The speed of sound in air is approximately 343 meters per second at room temperature. The formula for the speed of sound is:
Speed of sound = Frequency × Wavelength
In this problem, we are given the frequency (260 Hz) and the wavelength (1.29 m) of the sound wave. We can use these values to calculate the speed of sound:
Speed of sound = 260 Hz × 1.29 m = 335.4 m/s
Next, we need to use the fact that the man hears his echo 2 seconds after he shouted. Since the sound wave traveled from the man to the hill and then back to the man, the total distance traveled by the sound wave is twice the distance from the man to the hill. We can use the formula:
Distance = Speed × Time
to calculate the distance from the man to the hill:
Distance = (335.4 m/s) × (2 s/2) = 335.4 m
Therefore, the hill is 335.4 meters away from the man. The answer is option (B), 335.4m.
Question 40 Report
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