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JAMB UTME - Physics - 1991

Question 1 Report

A small metal ball thrown vertically upwards from the top of a tower with an initial velocity of 20ms-1. If the ball took a total of 6s to reach ground level, determine the height of the tower [g = 10ms-2]
Answer Details
Time from tower to top, t =  u − v g

=  20 − 0 10

= 2s

distance from tower to top

x = ut -  1 2 gt2

= (20 x 2) - ( 1 2  x 10 x 2 x 2)

= 20m

Time from the top to the ground, t = 6 - 2

= 4s

distance from top to ground,

x = ut -  1 2 gt2

= (0 x 4) + ( 1 2  x 10 x 4 x 4)

= 80cm

therefore, height of tower = 80 - 20

= 60m