JAMB UTME - Chemistry - 2004
Question 1 Report
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∴ The relative abundance of the isotope of mass 35 = (100 - x)%. Total mass of isotopes of mass 37 = 37x, while that of 35 = 35(100 - x)
∴ Total mass of the 100 atoms
= 37x + 35(100 - x) = 35.5
= 37x + 3500 - 35x = 35.5
∴ Mean mass of chlorine atom = (2x + 3500)/100 = 35.5
2x + 3500 = 3550; x = 50/2 = 25
Question 2 Report
C2H5OH(aq) → Y
If the above reaction takes place in conc. H2SO4 at 180o, Y represents
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Question 6 Report
N2O4(g) ? 2NO2(g)
In the endothermic reaction above, more product formation will be favoured by
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Question 9 Report
If a solution contains 4.9g of tetraoxosulphate (VI) acid, calculate the amount of copper (II) oxide that will react with it
[Cu = 64, O = 16, S = 32, H = 1]
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Question 12 Report
In the experiment above, X is a mixture of nitrogen, carbon (IV) oxide and
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Question 16 Report
22688Ra ? x86Rn + ? - particle
What is the value of x in the nuclear reaction above?
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Question 18 Report
Alkanol + Alkanoic ↔ Ester + Water
The reverse reaction above is known as
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Question 19 Report
What volume of gas is evolved at S.t.p if 2g of calcium trioxocarbonate (IV) is added to a solution of hydrochloric acid?
[Ca = 40, C = 12, O = 16, Cl = 35.5, H = 1 Molar volume of agas at s.t.p = 22.4 dm3
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The relative molecular mass of CaCO3 = 40 + 12 + 16 * 3 = 52 +48 = 100 ; Relative molecular mass of CO2 = 12 + 10 * 2 = 44
From the above equation, 100g of CaCO3reacts with 44g of CO2 at s.t.p. i.e 22.4 dm3
2g of CaCO3 will react with (2*22.4)/100 of CO2 = 0.448 dm3
0.448 dm3 = 0.448 * 1000 = 448cm3
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Question 28 Report
The mass of silver deposited when a current of 10a is passed through a solution of silver salt for 4830s is
[Ag = 108, F = 96500 c mol-1]
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Question 34 Report
2CO(g) + O2(g) → 2CO2(g)
Given that ΔH[CO]is -110.4 kJmol-1 and ΔH[CO2] is -393.0 kJmol-1, the energy change for the reaction above is
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= 7x - 393 - (7 * 110.4 + 0)
= -393 + 110.4 = -282.6 kJ
Question 35 Report
ZnO(s) + CO(g) → Zn(s) + CO2(g)
In the reaction above, Zinc has been
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Question 36 Report
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Question 37 Report
What volume of 0.5mldm3 H2SO4 will exactly neutralize 20cm3 of 0.1moldm3 NaOH Solution?
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2NaOH + H2SO4 ? Na2SO4 + 2H2O
CaVa) ÷ (CbVb) = ratio of acid / ratio of base
0.5Va ÷ (0.1 × 20) = ½
Va = 2.0cm3
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Question 41 Report
Calculate the solubility in mol dm-3 of 40g of CuSO4 dissolved in 100g of water at 120oC.
[Cu = 64, S = 32, O = 16]
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Question 44 Report
The IUPAC nomenclature of the compound above is
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Question 46 Report
CH3COOH(g) → H4(g) + CO2(g)
The reaction above is
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Question 49 Report
A given volume of methane diffuses in 20s. How long will it take the same volume of sulphur (IV) oxide to diffuse under the same conditions?
[C = 12, H = 1, S = 32, O = 16].
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Relative molecular mass of SO2 = 32 + 10 *2 = 64
tSO2/tCH4 = √MSO2/MCH4
t/20 = √64/16 = √4
t/20 = 2
∴ t = 20 * 2 = 40sec
Question 50 Report
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