Given that tan x = 23 2 3 , where 0o d" x d" 90o, Find the value of 2sinx.

Question 1 Report

Given that tan x = $\frac{2}{3}$ , where 0o d" x d" 90o, Find the value of 2sinx.

\frac{2 \sqrt{13}}{13}

\frac{3 \sqrt{13}}{13}

\frac{4 \sqrt{13}}{13}

\frac{6 \sqrt{13}}{13}

Answer Details

tan x = $\frac{2}{3}$ (given), is illustrated in a right-angled $Δ$
thus m2 = 22 + 32
= 4 + 9 = 13
m = $\sqrt{13}$
Hence, 2sin x = 2 x $\frac{2}{m}$
2 x $\frac{2}{\sqrt{13}}$
= $\frac{4}{\sqrt{13}}$
= $\frac{4}{\sqrt{13}} = \frac{\sqrt{13}}{\sqrt{13}}$
= $\frac{4 \sqrt{13}}{13}$

Read lesson note on Sine, Cosine And Tangent Of An Angle (WAEC)

Read lesson note on Trigonometry (JAMB)

Sine, Cosine And Tangent Of An Angle

Trigonometry

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