Question 1 Report
Integral ∫(5x3+7x2−2x+5) ( 5 x 3 + 7 x 2 − 2 x + 5 ) dx
Answer Details
∫[(x2+4x2+1)÷x2]dx=∫(x3/x2)dx+∫(1/x2)dx ∫ [ ( x 2 + 4 x 2 + 1 ) ÷ x 2 ] d x = ∫ ( x 3 / x 2 ) d x + ∫ ( 1 / x 2 ) d x ⇒∫xdx+∫4−1or+∫(1/x2)dx ∫ x d x + ∫ 4 − 1 o r + ∫ ( 1 / x 2 ) d x = x2/2−4x−1/x2+C
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