Find the equation of a line which is from the origin and passes through the point (−3, −4)

Find the equation of a line which is from the origin and passes through the point (−3, −4)

Answer Details

Equation of a straight line is given by
$y-y_1=m(x-x_1)$
Where m is the slope or gradient
Don't forget, the line passes through the origin. That means it has a coordinates of $\left\{0,0\right\}$ and $\left\{-3,-4\right\}$. So to calculate m
$m=\frac{\Delta y}{\Delta x}=\frac{0-(-4)}{0-(-3)}=\frac{4}{3}$
Equation of straight line is therefore given as:
$y-(-4)=\frac{4}{3}[x-(-3\left)\right]$
$3(y+4)=4(x+3)$
$3y+12=4x+12$
$3y=4x$
$\therefore y=\frac{4x}{3}$