Three electric cells each of e.m.f 1.5V and internal resistance of 1.0Ω Ω are connected in parallel across an external resistance of 23 2 3 Ω Ω . Calculate ...

Three electric cells each of e.m.f 1.5V and internal resistance of 1.0$\Omega$ are connected in parallel across an external resistance of $\frac{2}{3}$$\Omega$. Calculate the value of the current in the resistor

Answer Details

E.m.f = 1.5

r = $\frac{1\times 1\times 1}{(1\times 1)+(1\times 1)+(1\times 1)}$

r = $\frac{1}{3}$$\Omega$

I = $\frac{E.m.f}{r+R}$

I = $\frac{1.5}{\frac{1}{3}+\frac{2}{3}}$

I = 1.5A