Question 1 Report
Solve for (x, y) in the equation 2x + y = 4: x^2 + xy = -12
(6, -8): (-2, 8)
(3, -4): (-1, 4)
(8, -4): (-1, 4)
(-8, 6): (8, -2)
(-4, 3): (4, -1)
Answer Details
2x + y = 4......(i)x^2 + xy = -12........(ii)from eqn (i), y = 4 - 2x= x2 + x(4 - 2x)= -12x2 + 4x - 2x2 = -124x - x2 = -12x2 - 4x - 12 = 0(x - 6)(x + 2) = 0sub. for x = 6, in eqn (i) y = -8, 8=(6,-8); (-2, 8)