Find the equation of the locus of a point P(x,y) which is equidistant from Q(0,0) and R(2,1).
Answer Details
Locus of a point P(x,y) which is equidistant from Q(0,0) and R(2,1) is the perpendicular bisector of the straight line joining Q and R Mid point QR = (x2+x1)/2 . (y2+y1)/2 = 2+0/2 . 1+0/2