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Find the mean of the distribution above

Question 1 Report

Find the mean of the distribution above

1

2

3

4

Answer Details

M e a n = \frac{(0 \times 1) + (1 \times 2) + (2 \times 2) + (3 \times 1) + (4 \times 9)}{1 + 2 + 2 + 1 + 9} = \frac{(0 + 2 + 4 + 3 + 36)}{15} = \frac{45}{15} = 3

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Linear Inequalities

Measures Of Location

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