Fifty boxes each of 50 bolts were inspected for the number which were defective. The following was the result: No. defective per box456789No. of boxes271710...

Fifty boxes each of 50 bolts were inspected for the number which were defective. The following was the result:

$\begin{array}{ccccccc}\text{No. defective per box}& 4& 5& 6& 7& 8& 9\\ \text{No. of boxes}& 2& 7& 17& 10& 8& 6\end{array}$

The mean and the median of the distribution are respectively

Answer Details

To find the mean of the distribution, we need to calculate the sum of all the defective bolts in the boxes and divide it by the total number of boxes: Mean = (4x2 + 5x7 + 6x17 + 7x10 + 8x8 + 9x6) / 50 = 335 / 50 = 6.7 To find the median of the distribution, we need to arrange the data in order of increasing magnitude and find the middle value. In this case, we have an even number of observations (50), so the median will be the average of the two middle values, which are the 25th and 26th observations. From the table, we can see that the 25th and 26th observations are both 6, so the median is: Median = (6 + 6) / 2 = 6 Therefore, the mean and the median of the distribution are 6.7 and 6, respectively.