When element \(_{20}\)Y combines with element \(_8\)Z, it forms
Answer Details
The answer to the question depends on the electronic configuration and reactivity of the elements Y and Z. Element Y has an atomic number of 20, indicating it has 20 protons in its nucleus, while element Z has an atomic number of 8, indicating it has 8 protons in its nucleus.
To determine the type of compound formed, we need to consider the electronegativity of each element. Electronegativity is the measure of an atom's ability to attract electrons towards itself when it forms a chemical bond. Generally, when elements with a large difference in electronegativity combine, they form an ionic compound, while elements with similar electronegativity combine to form covalent compounds.
Since Y has a larger atomic number than Z, it has more electrons in its valence shell, making it less electronegative than Z. Therefore, Y is more likely to donate its electrons to Z, forming an ionic compound with the formula YZ. So, the correct option is "An ionic compound, YZ is formed."