Question 1 Report
Find the derivative of sinθcosθ
Answer Details
sinθcosθ sin θ cos θ cosθd(sinθ)dθ−sinθd(cosθ)dθcos2θ cos θ d ( sin θ ) d θ − sin θ d ( cos θ ) d θ cos 2 θ cosθ.cosθ−sinθ(−sinθ)cos2θ cos θ . cos θ − sin θ ( − sin θ ) c o s 2 θ cos2θ+sin2θcos2θ c o s 2 θ + sin 2 θ c o s 2 θ Recall that sin2 θ θ + cos2 θ θ = 1 1cos2θ 1 cos 2 θ = sec2 θ
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