Find the sum of the first 18 terms of the series 3, 6, 9,..., 36.

Assessment: JAMB UTME - Mathematics - 2011 Subject: General Mathematics

Question 1 Report

Find the sum of the first 18 terms of the series 3, 6, 9,..., 36.
Answer Details
3, 6, 9,..., 36.
a = 3, d = 3, i = 36, n = 18
Sn =  n 2  [2a + (n - 1)d
S18 =  18 2  [2 x 3 + (18 - 1)3]
= 9[6 + (17 x 3)]
= 9 [6 + 51] = 9(57)
= 513

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