Question 1 Report
Find the sum of the first 18 terms of the series 3, 6, 9,..., 36.
Answer Details
3, 6, 9,..., 36. a = 3, d = 3, i = 36, n = 18 Sn = n2 n 2 [2a + (n - 1)d S18 = 182 18 2 [2 x 3 + (18 - 1)3] = 9[6 + (17 x 3)] = 9 [6 + 51] = 9(57) = 513
Simplify \(\frac{3\frac{2}{3}\times\frac{5}{6}\times\frac{2}{3}}{\frac{11}{15}\times\frac{3}{4}\times\frac{2}{27}}\)
If 2q35 = 778, find q
If the numbers M, N, Q are in the ratio 5:4:3, find the value of \( \frac{2N-Q}{M} \)
Rationalize \( \frac{2-\sqrt{5}}{3-\sqrt{5}} \)
Simplify \( \left(\frac{16}{81}\right)^{\frac{1}{4}} \div \left(\frac{9}{16}\right)^{-\frac{1}{2}} \)
If log318 + log33 - log3x = 3, Find x.
Simplify \(\left(\sqrt{2}+\frac{1}{\sqrt{3}}\right)\left(\sqrt{2}-\frac{1}{\sqrt{3}}\right)\)
A man invested ₦5,000 for 9 months at 4%. What is the simple interest?
Everything you need to excel in JAMB, WAEC & NECO