Find ∫10 ∫ 0 1 cos4 x dx

Question 1 Report

Find $\int_{0}^{1}$ cos4 x dx

\frac{3}{4}

sin 4x + k

\frac{1}{4}

sin 4x + k

\frac{3}{4}

sin 4x + k

\frac{1}{4}

sin 4x + k

Answer Details

$\int_{0}^{1}$ cos4 x dx
let u = 4x
$\frac{d y}{d x}$ = 4
dx = $\frac{d y}{4}$
$\int_{0}^{1}$ cos u. $\frac{d y}{4}$ = $\frac{1}{4}$ $\int$ cos u du
= $\frac{1}{4}$ sin u + k
= $\frac{1}{4}$ sin4x + k

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Integration

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