class1−34−67−9Frequency585 c l a s s 1 − 3 ..

Question 1 Report

$\begin{array}{cc} c l a s s & 1 - 3 & 4 - 6 & 7 - 9 \\ F r e q u e n c y & 5 & 8 & 5 \end{array}$

Find the standard deviation of the data using the table above

\(\sqrt{6}\0

\frac{5}{3}

\sqrt{5}

Answer Details

$\begin{matrix} class intervals & F r e (F) & class-marks(x) & F x & (x - x) & (x - x)^{2} & F (x - x)^{2} \\ 1 - 3 & 5 & 10 & 10 & - 3 & 9 & 90 \\ 4 - 6 & 8 & 40 & 40 & 0 & 0 & 0 \\ 7 - 9 & 5 & 40 & 40 & 3 & 9 & 360 \\ 18 & 90 & 450 \end{matrix}$
x = $\frac{\sum f x}{\sum f}$
= $\frac{90}{18}$
= 5
S.D = $\frac{\sum f (x - x)^{2}}{\sum f}$
= $\frac{450}{18}$
= $\sqrt{25}$
= 5

View Answer

class1−34−67−9Frequency585 c l a s s 1 − 3 4 − 6 7 − 9 F r e q u e n c y 5 8 5 Find the standard deviation of the data using the table above