Two strings of the same length and under the same tension gives notes of frequencies in the ratio 4 : 1. The masses of the strings are in the corresponding

Question 1 Report

2 : 1

1 : 2

1 : 4

1 : 16

Answer Details

F = $\frac{1}{2 L}$ $\sqrt{\frac{T}{m}}$

$\frac{F_{1}}{F_{2}}$ = $\sqrt{\frac{m_{2}}{m_{1}}}$

$\frac{1}{4}$ = $\sqrt{\frac{m_{2}}{m_{1}}}$

$\sqrt{\frac{m_{2}}{m_{1}}}$ = $\frac{1}{2}$

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