If \(P = \sqrt{QR\left(1+\frac{3t}{R}\right)}\), make R the subject of the formula.
Answer Details
To make R the subject of the formula, we need to isolate R on one side of the equation.
Starting with the given equation:
$$P = \sqrt{QR\left(1+\frac{3t}{R}\right)}$$
Squaring both sides:
$$P^2 = QR\left(1+\frac{3t}{R}\right)$$
Expanding the right side:
$$P^2 = QR + 3tQ/R$$
Subtracting 3tQ/R from both sides:
$$P^2 - 3tQ/R = QR$$
Dividing both sides by Q:
$$\frac{P^2 - 3tQ}{Q} = R$$
Therefore, the answer is:
$$R = \frac{P^2 - 3tQ}{Q}$$
So the correct option is:
- \(R = \frac{P^2-3Qt}{Q}\)