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If \(\frac{3^{(1-n)}}{9^{-2n}}=\frac{1}{9}\) find n
Question 1
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If \(\frac{3^{(1-n)}}{9^{-2n}}=\frac{1}{9}\) find n
\(-\frac{3}{2}\)
\(\frac{1}{3}\)
-1
-3
Answer Details
Read lesson note on Indices (WAEC)
Indices
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