Potassium trioxochlorate (V)has a solubility of 1.5 mol dm -3 at 45 oC.On cooling this solution to a temperature of 20 oC, the solubility was found to be 0....

Assessment: JAMB UTME - Chemistry - 2012 Subject: Chemistry

Question 1 Report

Potassium trioxochlorate (V)has a solubility of 1.5 mol dm -3 at 45 oC.On cooling this solution to a temperature of 20 oC, the solubility was found to be 0.5 mol dm -3. What mass of KCIO 3 was crystalized out?

[K = 39, Cl = 35.5 O =16].

Answer Details
To calculate the mass of KCIO3 crystallized out, we can use the following formula: Mass = (initial solubility - final solubility) x volume x molar mass of KCIO3 First, let's calculate the difference in solubility: 1.5 mol dm^-3 - 0.5 mol dm^-3 = 1.0 mol dm^-3 Next, we need to convert the volume from dm^3 to liters: 1 dm^3 = 1 liter Now we can substitute the values into the formula: Mass = 1.0 mol dm^-3 x 1 liter x 122.5 g mol^-1 Mass = 122.5 g Therefore, the mass of KCIO3 crystallized out is 122.5 g. Note that the molar mass of KCIO3 can be calculated as follows: Molar mass = (1 x atomic mass of K) + (1 x atomic mass of Cl) + (3 x atomic mass of O) Molar mass = (1 x 39.1 g mol^-1) + (1 x 35.5 g mol^-1) + (3 x 16.0 g mol^-1) Molar mass = 122.5 g mol^-1 The correct answer is: 122.50g.

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