The data shows the marks obtained by students in a biology test 52 56 25 56 68 73 66 64 56 48 20 39 9 50 46 54 54 40 50 96 36 44 18 97 65 21 60 44 54 32 92 ...

Question 1 Report

The data shows the marks obtained by students in a biology test

52	56	25	56	68	73	66	64	56	48
20	39	9	50	46	54	54	40	50	96
36	44	18	97	65	21	60	44	54	32
92	49	37	94	72	88	89	35	59	34
15	88	53	16	84	52	72	46	60	42

(a) Construct a frequency distribution table using the class interval 0 - 9, 10 - 19, 19, 20, 29...

(b) Draw a cumulative frequency curve for the distribution

(c) Use the graph to estimate the;

(i) median

(ii) Percentage of students who scored at least 66 marks, correct to the nearest whole number.

Answer

a)

Class Intervals	Class Boundaries	Frequency	Cumulative Frequency
0 - 9	0.5 - 9.5	1	1
10 - 19	9.5 - 19.5	3	4
20 - 29	19.5 - 29.5	3	7
30 - 39	29.5 - 39.5	6	13
40 - 4921	39.5 - 49.5	8	21
50 - 59	49.5 - 59.5	12	33
60 - 69	59.5 - 69.5	6	39
70 - 79	69.5 - 79.5	3	42
80 - 89	79.5 - 89.5	4	46
90 - 99	89.5 - 99.5	4	50
		$\sum f = 50$

b)

(c)

(i) Mean mark

= 49.9

(ii) Percentage of at least 66 mark

= $\frac{13}{50} \times 100$ %

= 26%

Read lesson note on Representation Of Data (JAMB)

Read lesson note on Inequalities (JAMB)

Read lesson note on Lengths And Perimeters (WAEC)

Answer Details

a)

Class Intervals	Class Boundaries	Frequency	Cumulative Frequency
0 - 9	0.5 - 9.5	1	1
10 - 19	9.5 - 19.5	3	4
20 - 29	19.5 - 29.5	3	7
30 - 39	29.5 - 39.5	6	13
40 - 4921	39.5 - 49.5	8	21
50 - 59	49.5 - 59.5	12	33
60 - 69	59.5 - 69.5	6	39
70 - 79	69.5 - 79.5	3	42
80 - 89	79.5 - 89.5	4	46
90 - 99	89.5 - 99.5	4	50
		$\sum f = 50$

b)

(c)

(i) Mean mark

= 49.9

(ii) Percentage of at least 66 mark

= $\frac{13}{50} \times 100$ %

= 26%

Read lesson note on Representation Of Data (JAMB)

Read lesson note on Inequalities (JAMB)

Read lesson note on Lengths And Perimeters (WAEC)

Representation Of Data

Inequalities

Lengths And Perimeters

View Answer