(a) If logo a = 1.3010 and log\(_{10}\)b - 1.4771. find the value of ab
(ii) angle BAC.
(a)
We know that log10a = 1.3010. Therefore, we can use the definition of logarithms to write:
10^1.3010 = a
a = 19.9526
We also know that log10b = 1.4771. Using the same process as above, we can find that:
10^1.4771 = b
b = 30.059
Finally, we can find the value of ab by multiplying these two values:
ab = 19.9526 * 30.059
ab = 600.001
Therefore, ab is approximately equal to 600 (to the nearest whole number).
(b)
A
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e | \ c
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-------O-----
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| / d
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B
We can start by using the fact that angles in a triangle add up to 180 degrees. Therefore, angle AOB is:
angle AOB = 180 - angle ACB
angle AOB = 180 - 39
angle AOB = 141
Since O is the center of the circle, we know that AC and BC are radii of the circle. Therefore, they are equal in length. We can use this fact to find the length of CD, since angle CDE is a right angle:
CD = AC = BC
CD = d
sin(62) = CD/CE
CD = CE * sin(62)
Now we can use the cosine rule to find the length of CE:
CE^2 = AC^2 + AE^2 - 2(AC)(AE)cos(39)
CE^2 = d^2 + e^2 - 2de(cos(141))
We can also use the cosine rule to find the