A function is defined by \(f(x) = \frac{3x + 1}{x^{2} - 1}, x \neq \pm 1\). Find f(-3).
Answer Details
To find f(-3), we substitute -3 in the given function:
\(f(-3) = \frac{3(-3) + 1}{(-3)^2 - 1} = \frac{-8}{8} = -1\)
Therefore, the value of f(-3) is -1.
So, the answer is (B) \(-1\).