(a) Evaluate and express your answer in standard form : \(\frac{4.56 \times 3.6}{0.12}\) (b) Without using mathematical tables or calculator, evaluate \((73...

Assessment: WAEC SSCE - General Mathematics - 2000 (Essay) Subject: General Mathematics

Question 1 Report

(a) Evaluate and express your answer in standard form : \(\frac{4.56 \times 3.6}{0.12}\)

(b) Without using mathematical tables or calculator, evaluate \((73.8)^{2} - (26.2)^{2}\).

(c) Simplify \(\sqrt{1\frac{19}{81}}\), expressing your answer in the form \(\frac{a}{b}\) where a and b are positive integers.

Answer Details

(a)

\[\frac{4.56\times3.6}{0.12} = \frac{16.416}{0.12} = 136.8 = 1.368\times10^{2}.\]

(b) Use the difference of two squares \(a^2 - b^2 = (a-b)(a+b)\):

\[(73.8)^2 - (26.2)^2 = (73.8 - 26.2)(73.8 + 26.2) = 47.6\times100 = 4760.\]

(c) Convert the mixed number to an improper fraction:

\[1\tfrac{19}{81} = \frac{81 + 19}{81} = \frac{100}{81},\qquad \sqrt{\frac{100}{81}} = \frac{10}{9}.\]

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