Question 1 Report
A 500W heater is used to heat 0.6kg of water from \(25^\circ\mathrm{C}\) to \(100^\circ\mathrm{C}\) in \(t_2\) seconds. If another 1000W heater is used to heat 0.2kg of water from \(10^\circ\mathrm{C}\) to \(100^\circ\mathrm{C}\) in t, seconds, find \(\frac{t_1}{t_2}\)
Heat energy = Electrical energy
mc = power x time
0.6 x c x (100 - 25) = 500 x t1
and, 0.2 x c x (100 - 10)= 100 x t2
= 5
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