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If \(16^{3x} = \frac{1}{4}(32^{x - 1})\), find the value of x.
Question 1
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If \(16^{3x} = \frac{1}{4}(32^{x - 1})\), find the value of x.
\(-1\)
\(\frac{-1}{3}\)
\(\frac{-3}{7}\)
\(\frac{-5}{19}\)
Answer Details
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