If \(16^{3x} = \frac{1}{4}(32^{x - 1})\), find the value of x.

Question 1 Report

If \(16^{3x} = \frac{1}{4}(32^{x - 1})\), find the value of x.

\(-1\)

\(\frac{-1}{3}\)

\(\frac{-3}{7}\)

\(\frac{-5}{19}\)

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