Two capacitance of 6μ μ F and 8μ μ F are connected in series. What additional capacitance must be connected in series with this combination to give a total ...

Two capacitance of 6$\mu$F and 8$\mu$F are connected in series. What additional capacitance must be connected in series with this combination to give a total of 3$\mu$F

Answer Details

3 = $\frac{6\times 8\times c}{(6\times 8)+(6\times c)+(8\times c}$

therefore, C = 24$\mu$F