Two capacitance of 6μ μ F and 8μ μ F are connected in series. What additional capacitance must be connected in series with this combination to give a total ...

Question 1 Report

Two capacitance of 6 $μ$ F and 8 $μ$ F are connected in series. What additional capacitance must be connected in series with this combination to give a total of 3 $μ$ F

μ

μ

μ

μ

Answer Details

3 = $\frac{6 \times 8 \times c}{(6 \times 8) + (6 \times c) + (8 \times c}$

therefore, C = 24 $μ$ F

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Capacitors

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