A pool of water appears to be 1.0m deep when viewed vertically from above. If the refractive index of water is 1.33, what is the actual depth of the pool?

A pool of water appears to be 1.0m deep when viewed vertically from above. If the refractive index of water is 1.33, what is the actual depth of the pool?

Answer Details

n = $\frac{\text{real depth}}{\text{apparent depth}}$

1.33 = $\frac{\text{real depth}}{1}$

real depth = 1.33cm