A load of 5N gives an extension of 0.56cm i..

Question 1 Report

A load of 5N gives an extension of 0.56cm in a wire which obeys Hooke's law. What is the extension caused by a load of 20N?

1.12cm

2.14cm

2.24cm

2.52cm

Answer Details

$\frac{F_{1}}{e_{1}}$ = $\frac{F_{2}}{e_{2}}$

$\frac{5}{0.56}$ = $\frac{20}{e_{2}}$

e2 = 2.24cm