Question

If sin $\theta$ = $\frac{m - n}{m + n}$; Find the value of 1 + tan2$\theta$

Accepted Answer

$\frac{(m^2 + n^2 + 2mn)}{4mn}$

Answer

$\frac{(m^2 + n^2)}{m + n}$

Answer

$\frac{2(m^2 + n^2 + mn)}{m + n}$

Answer

$\frac{(m^2 + n^2 + mn)}{m + n}$

If sin \(\theta\) = \(\frac{m - n}{m + n}\); Find the value of 1 + tan2\(\theta\)