If \( \tan \theta = \frac{m^2-n^2}{2mn} \) find \( \sec \theta \)

Assessment: JAMB UTME - Mathematics - 1987 Subject: General Mathematics

Question 1 Report

If \( \tan \theta = \frac{m^2-n^2}{2mn} \) find \( \sec \theta \)

Answer Details
Tan  θ  =  m 2 − n 2 2 m n
Opp Adj  by pathagoras theorem
= Hyp2 = Opp2 + Adj2
Hyp2 = (m2 - n2) + (2mn)2
Hyp2 = m4 - 2m2n4 - 4m2 - n2
Hyp2 = m4 + 2m2 + n2n
Hyp2 = (m2 - n2)2
Hyp2 = 

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