If tan θ θ = m2−n22mn m 2 − n 2 2 m n find secθ

Question 1 Report

If tan $θ$ = $\frac{m^{2} - n^{2}}{2 m n}$ find sec $θ$

m²+n²

(m²−n²)

m²+n²

2mn

mn

2(m²+n²⁾

m²n²

2m²−n²

Answer Details

Tan $θ$ = $\frac{m^{2} - n^{2}}{2 m n}$
$\frac{Opp}{Adj}$ by pathagoras theorem
= Hyp2 = Opp2 + Adj2
Hyp2 = (m2 - n2) + (2mn)2
Hyp2 = m4 - 2m2n4 - 4m2 - n2
Hyp2 = m4 + 2m2 + n2n
Hyp2 = (m2 - n2)2
Hyp2 = $\frac{m^{2} + n^{2}}{2 m n}$

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