Question 1 Report
If a u2 - 3v2 and b = 2uv + v2 evaluate (2a - b)(a - b2), when u = 1 and v = -1
Answer Details
a = u2 - 3y2 = (1)2 - 3(-1) = -2 b = 2uu + v2 + v2 = 2(1)(-1) + (-1)2 = -1 ∴ 2(2a - b)(a - b∴) = [2(-2) - 1](-2 - (-1)2) = -3 - 3 = 9
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