In the diagram above, O is the center of the circle, BOC is a diameter and angle ADC is 37o What is ACB?

Assessment: WAEC SSCE - General Mathematics - 1988 (Objective) Subject: General Mathematics

Question 1 Report

In the diagram above, O is the center of the circle, BOC is a diameter and angle ADC is 37o
What is ACB?

Answer Details
Since BOC is a diameter, then angle BAC is 90 degrees (as it is an inscribed angle that subtends a diameter). Also, angle ADC is 37 degrees (given). Therefore, angle ACB can be found using the fact that the angles in a triangle sum to 180 degrees. Thus: angle ACB = 180 - angle BAC - angle ADC = 180 - 90 - 37 = 53 degrees Therefore, the answer is 53 degrees.
Read lesson note on Circles (WAEC)
View Answer

Related Questions

1

Evaluate (101.5)2 - (100.5)2
2

A group of students took a test and the following frequency table shows the scores above Find the mode
3

Simplify 36\(^\frac{1}{2}\) x 64\(-^\frac{1}{3}\) x 5\(^0\)
4

A group of students took a test and the following frequency table shows the scores above The median score is
5

Express the product of 0.06 and 0.09 in standard form
6

A group of students took a test and the following frequency table shows the scores above The mean score is
7

Find the 8th term of the A.P -3, -1, 1 ......
8

If cos 60° = 1/2, which of the following angle has cosine of -1/2?

Download The App On Google Playstore

Everything you need to excel in your exams

Green Bridge CBT Mobile App
Personalized AI Learning Chat Assistant
200,000+ Exam Questions Across IGCSE, JAMB, WAEC & NECO
Over 3,900 Lesson Notes
Offline Support - Learn Anytime, Anywhere
Green Bridge Timetable
Literature Summaries & Potential Questions
Track Your Performance & Progress
In-depth Explanations for Comprehensive Learning