Using the diagram above, calculate the relative density of x, if the density of methanol is 800kgm−3

density of methanol =  800kgm−3 ${}^{-3}$ → 0.8gcm−3 ${}^{-3}$ 

At equilibrium, the density of methanol = the density of liquid x

ρ $\rho$ x h x g = ρ $\rho$x ${}_x$ x hx ${}_x$ x g

0.8 x 7.1 =  ρ $\rho$x ${}_x$ x  14.2

 ρ $\rho$x ${}_x$ = 0.8×7.114.2 $\frac{0.8\times 7.1}{14.2}$ = 0.4gcm−3 ${}^{-3}$ 

∴ $\therefore$, the relative density of liquid x = 0.4

Relative density of X = density of liquid xdensity of methanol $\frac{\text{density of liquid x}}{\text{density of methanol}}$ = 0.40.8 $\frac{0.4}{0.8}$ = 0.5