Question 1 Report
The value of R in the above circuit to make the galvanometer measure 2A is
Answer Details
Given: Ig g = 50mA = 0.05A, I to be measured = 2A, r = 2Ω Ω , Is s = I - Ig g = 2 - 0.05 = 1.95A
Shunt(R) = IgIs I g I s x r
R = 0.051.95 0.05 1.95 x 10 = 0.2564Ω