Question 1 Report
In the figure, \( \triangle \)PQT is isosceles. PQ = QT, SRQ = \(35^\circ\), TPQ = \(20^\circ\) and PQR is a straight line.Calculate TSR
Answer Details
Given △ △ isosceles PQ = QT, SRQ = 35∘ ∘
TPQ = 20∘ ∘
PQR = is a straight line
Since PQ = QT, angle P = angle T = 20∘ ∘
Angle PQR = 180∘ ∘ - (20 + 20) = 140∘ ∘
TQR = 180∘ ∘ - 140∘ ∘ = 40∘ ∘ < on a straight line
QSR = 180∘ ∘ - (40 + 35)∘ ∘ = 105∘ ∘
TSR = 180∘ ∘ - 105∘ ∘
= 75∘
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