Question 1 Report
In the figure, \( \triangle \)PQT is isosceles. PQ = QT, SRQ = \(35^\circ\), TPQ = \(20^\circ\) and PQR is a straight line.Calculate TSR
TPQ = 20
PQR = is a straight line
Since PQ = QT, angle P = angle T = 20
Angle PQR = 180 - (20 + 20) = 140
TQR = 180 - 140 = 40 < on a straight line
QSR = 180 - (40 + 35) = 105
TSR = 180 - 105
= 75
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