Solve the equation 3x2 + 6x - 2 = 0

Assessment: JAMB UTME - Mathematics - 1986 Subject: General Mathematics

Question 1 Report

x = -1

\pm

\frac{\sqrt{3}}{3}

x = -1

\pm

\frac{\sqrt{15}}{3}

x = -2

\pm

2

x = 3

\pm

\frac{\sqrt{3}}{15}

Answer Details

3x2 + 6x - 2 = 0
Using almighty formula i.e. x =

\frac{b \pm \sqrt{b^{2} - 4 a c}}{2 a}

a = 3, b = 6, c = -2
x =

\frac{- 6 \pm \sqrt{6^{2} - 4 (3) (- 2)}}{2 (3)}

x =

\frac{6 \pm \sqrt{36 - 24}}{6}

x =

\frac{6 \pm \sqrt{60}}{6}

x =

\frac{- 6 \pm \sqrt{4 \times 15}}{6}

x =

\frac{- 1 \pm \sqrt{15}}{3}

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