Calculate the upthrust on an object of volume 50cm3 which is immersed in liquid of density 103kgm-3 [g = 10ms-2]
Question 1 Report
Calculate the upthrust on an object of volume 50cm3 which is immersed in liquid of density 103kgm-3 [g = 10ms-2]
Answer Details
To calculate the upthrust on an object immersed in a fluid, we need to use Archimedes' principle which states that the upthrust (buoyant force) experienced by an object partially or fully submerged in a fluid is equal to the weight of the fluid displaced by the object.
First, let's convert the volume of the object into meters cubed:
50 cm^3 = (50/100)^3 m^3 = 0.0005 m^3
The weight of the liquid displaced by the object is:
density of liquid x volume of liquid displaced x acceleration due to gravity
= 103 kg/m^3 x 0.0005 m^3 x 10 m/s^2
= 0.515 N
Therefore, the upthrust (buoyant force) acting on the object is 0.515 N.
So, the correct answer is option C: 0.5N.
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