The velocity ratio of an inclined plane where angle of inclination in θ is

The velocity ratio of an inclined plane where angle of inclination in θ is

Answer Details

Consider an inclined plane shown below, as the effort moves along OB, the load moves is lifted up through a vertical height AB

V.R = $\frac{\text{distance moved by effort}}{\text{distance moved by load}}$ = $\frac{OB}{AB}$

But Sinθ = $\frac{opp}{hyp}$ = $\frac{AB}{OB}$

therefore; = $\frac{OB}{AB}$ = $\frac{1}{\sin \theta }$