From the diagram above, calculate the total current in the circuit

Assessment: JAMB UTME - Physics - 2017 Subject: Physics

Question 1 Report

5.0A

3.7A

4.5A

4.0A

Answer Details

V = IR from ohms law

I = $\frac{V}{R}$

Since the resistance are in parallel

$\frac{1}{R e f f}$ = $\frac{1}{8}$ + $\frac{1}{12}$ + $\frac{1}{6}$

= $\frac{2 + 3 + 6}{36}$ = $\frac{11}{36}$

Reff = $\frac{36}{11}$ = 3.27

I = I1 + I2 + I3

= $\frac{V}{R e f f}$ = $\frac{12}{3.27}$

= 3.669A

I = 3.7A

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