Calculate the electric field intensity between two plates of potential difference 6.5V when separated by a distance of 35cm.

Assessment: JAMB UTME - Physics - 2017 Subject: Physics

Question 1 Report

Calculate the electric field intensity between two plates of potential difference 6.5V when separated by a distance of 35cm.
Answer Details
The electric field intensity E between two parallel plates of potential difference V separated by a distance d is given by E = V/d. Substituting the given values, we have E = 6.5V/0.35m = 18.57 NC^−1. Therefore, the electric field intensity between the two plates is 18.57 NC^−1. Answer: 18.57NC^−1
Read lesson note on Electric Field (WAEC)
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