Question 1 Report
(a)(i) Define hard water
(ii) Name two substances responsible for hardness in water
(iii) Give two methods for the removal of hardness in water.
(b)(i) What are the raw materials require for the manufacture of tetraoxosulphate (VI) acid by the contact process?
(ii) Write an equation for tr reaction that requires a catalyst in the contact process (iii) State the catalyst used in (b)(ii).
(c)(i) Give two uses of sodium tetraoxosulphate (VI) Consider the reaction represented by the following equation:
Na\(_2\)SO\(_4\).10H\(_2\)O\(_{(s)}\) \(\to\) Na\(_2\)SO\(_4\).H\(_2\)O + 9H\(_2\)O\(_{(g)}\)
(ii) What name is given to this type of reaction?
(iii) Calculate the solubility of Na\(_2\)CO\(_3\) at 25°C. if 30.0 cm\(^3\) of its saturated solution at that temperature gave 1.80 g of the anhydrous salt. [C = 12, 0 = 16, Na = 23]
(d)(i) Define the term activated complex
(ii) State one reason why a collision may not produce a chemical reaction
(iii) The formation of water gas is represented by the following equation:
C\(_{(s)}\) + H\(_2\)O\(_{(g)}\) \(\to\) CO\(_{(g)}\) + H\(_{2(0)}\) \(\Delta\)H= + 131 kJmol\(^{-1}\)
Draw an energy profile diagram for the reaction showing the I. activated complex, II. enthalpy of reactants.
(a)(i) Definition of hard water
Hard water is water that does not readily form a lather with soap.
(a)(ii) Substances responsible for hardness
Other acceptable substances include calcium sulphate, magnesium hydrogencarbonate and magnesium chloride. Calcium and magnesium ions cause hardness.
(a)(iii) Removal of hardness
Ion-exchange resins (permutit) and distillation are also acceptable methods.
(b)(i) Raw materials for the Contact process
Sulphur and air (or oxygen) are the main raw materials. Sulphur is burned in air to form sulphur dioxide.
(b)(ii) Catalysed reaction in the Contact process
\[ 2\mathrm{SO_2(g)} + \mathrm{O_2(g)} \rightleftharpoons 2\mathrm{SO_3(g)} \]
(b)(iii) Catalyst
Vanadium(V) oxide, \( \mathrm{V_2O_5} \).
(c)(i) Uses of sodium tetraoxosulphate(VI), \( \mathrm{Na_2SO_4} \)
(c)(ii) Type of reaction
\[ \mathrm{Na_2SO_4 \cdot 10H_2O(s) \rightarrow Na_2SO_4 \cdot H_2O(s) + 9H_2O(g)} \]
This reaction is called efflorescence. The hydrated salt loses some of its water of crystallisation.
(c)(iii) Solubility of \( \mathrm{Na_2CO_3} \) at \(25^\circ\mathrm{C}\)
Mass of anhydrous \( \mathrm{Na_2CO_3} \) in \(30.0\ \mathrm{cm^3}\) of saturated solution \(=1.80\ \mathrm{g}\).
\[ \text{Mass in }1000\ \mathrm{cm^3} = \frac{1000 \times 1.80}{30.0} = 60.0\ \mathrm{g} \]
\[ M_r(\mathrm{Na_2CO_3}) = 2(23)+12+3(16)=106 \]
\[ \text{Solubility} = \frac{60.0}{106}=0.566\ \mathrm{mol\,dm^{-3}} \]
Therefore, the solubility is \(0.566\ \mathrm{mol\,dm^{-3}}\) (or \(60.0\ \mathrm{g\,dm^{-3}}\)).
(d)(i) Activated complex
An activated complex is a temporary, unstable, high-energy arrangement of atoms formed when reacting particles collide effectively, before products are formed.
(d)(ii) Reason a collision may not cause a reaction
The colliding particles may have energy less than the activation energy. Therefore, they cannot form the activated complex. A collision may also fail if the particles have an unsuitable orientation.
(d)(iii) Energy profile diagram for the formation of water gas
The reaction has \( \Delta H=+131\ \mathrm{kJ\,mol^{-1}} \), so it is endothermic: the products are at a higher enthalpy level than the reactants.
The key feature is that the products are higher than the reactants, because a positive \( \Delta H \) means energy is absorbed overall.
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