Eight alpha decays and six beta decays are necessary before an atom of \( {}^{238}_{92}\mathrm{U} \) achieves stability. The final product in the chain has ...
Question 1 Report
Eight alpha decays and six beta decays are necessary before an atom of \( {}^{238}_{92}\mathrm{U} \) achieves stability. The final product in the chain has an atomic number of
Answer Details
U 8() + 6() +
92 = (8 X 2) + (6 X -1) + a
a = 82
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