Eight alpha decays and six beta decays are necessary before an atom of 2 23892U 92 238 U achieves stability. The final product in the chain has an atomic nu...

Question 1 Report

Eight alpha decays and six beta decays are necessary before an atom of 2 $_{92}^{238} U$ achieves stability. The final product in the chain has an atomic number of

Answer Details

U $\to$ 8( $_{2}^{4} H e$ ) + 6( $_{- 1}^{0} e$ ) + $_{a}^{b} X$

92 = (8 X 2) + (6 X -1) + a

a = 82

Read lesson note on Structure Of The Atom (Nigeria Only) (WAEC)

Structure Of The Atom (Nigeria Only)

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