The magnification of the image of an object placed in front of a convex mirror is 13 1 3 . If the radius of curvature of the mirror is 24cm, what is the dis...

The magnification of the image of an object placed in front of a convex mirror is $\frac{1}{3}$. If the radius of curvature of the mirror is 24cm, what is the distance between its object and its image?

Answer Details

F = uv ; v = 1u

12 = $\frac{v+3v}{v+3v}$

v = 16cm, u = 48cm

distance between U and V

= 48 - 16 =32cm