Question 1 Report
Evaluate1∫0x2(x3+2)3
5612
6512
12
65
Answer Details
1∫0x2(x3+2)3 3 dx
let u=x3+2,du=3x2dx
when x = 1, u = 3
when x = 0, u = 2
dx = du3x2
3∫2 3 2 ∫ x2[u]33x2
3∫2 3 2 ∫ u33 du
= u43∗4 2 3
112[u4] 2 3
112[34−24] 1 12 [ 3 4 − 2 4 ]
112[81−16] 1 12 [ 81 − 16 ]