A body of mass of 18kg is suspended by an inextensible string from a rigid support and is pulled by a horizontal force F until the angle of inclination of t...

Answer Details

If the system is in equilibrium, then the weight of the body = the force pulling it
and the force = the vertical component of force F
since Force F is inclined to vertical then the vertical component = Fcos35º
the weight of the body = mg
Fcos35º = 18(10)
0.8192F = 180

F = 1800.8192 $\frac{\mathrm{<br>}}{}$

F = 219.7N

tension in the string

T = mg
T = 18kg × 10
T = 180N