Solve 2(2y+1)−5(2y)+2 − 5 + 2 = 0

Solve 2(2y+1)−5(2y)+2 $-5<br>+2$ = 0

Answer Details

2(2y+1)−5(2y)+2 ${\mathrm{<br>}}^{}$ = 0

Let p = 2y ${}^{\mathrm{<br>}}$
22y(21)−5(2y) ${\mathrm{<br>}}^{}$ + 2 = 0
2p2 ${}^2$ - 5p + 2 = 0
2p2 ${}^2$ - p - 4p + 2 = 0
p (2p - 1) - 2(2p - 1) = 0
(p - 2)(2p - 1) = 0

p = 2 or 12 $\frac{1}{2}$

p = 2y ${}^{\mathrm{<br>}}$
when p = 2
2y ${}^{\mathrm{<br>}}$ = 2
y = 1

when p = 12 $\frac{\mathrm{<br>}}{}$

2y ${}^{\mathrm{<br>}}$ = 12 $\frac{\mathrm{<br>}}{}$

2y ${}^{\mathrm{<br>}}$ = 2−1 ${}^{<br>}$

y = -1

y = -1 or 1