Two rays of light from a point below the surface of water are equally inclined to each other at $60^\circ$ in water. What is the angle between the rays wh...

Assessment: JAMB UTME - Physics - 1985 Subject: Physics

Question 1 Report

Two rays of light from a point below the surface of water are equally inclined to each other at $60^\circ$ in water. What is the angle between the rays when they emerge into air? (Take the refractive index of water to be $\frac{4}{3}$)

41.8o

44.1o

60.0o

83.6o

120.0o

Answer Details

$\frac{4}{3}$ = $\frac{s i n r_{1}}{s i n 30}$ and $\frac{4}{3}$ = $\frac{s i n r_{2}}{s i n 30}$

r1 = 41.8o and r2 = 41.8o

angle between them = r1 + r2

= 83.6o

Read lesson note on Refraction Of Light Through Plane And Curved Surfaces (JAMB)

Refraction Of Light Through Plane And Curved Surfaces

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Two rays of light from a point below the surface of water are equally inclined to each other at \(60^\circ\) in water. What is the angle between the rays wh...

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Two rays of light from a point below the surface of water are equally inclined to each other at \(60^\circ\) in water. What is the angle between the rays wh...

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