Two rays of light from a point below the surface of water are equally inclined to each other at 60o in water. What is the angle between the rays when they e...

Question 1 Report

Two rays of light from a point below the surface of water are equally inclined to each other at 60o in water. What is the angle between the rays when they emerge into air? (Take the refractive index of water to be $\frac{4}{3}$ )

41.8o

44.1o

60.0o

83.6o

120.0o

Answer Details

$\frac{4}{3}$ = $\frac{s i n r_{1}}{s i n 30}$ and $\frac{4}{3}$ = $\frac{s i n r_{2}}{s i n 30}$

r1 = 41.8o and r2 = 41.8o

angle between them = r1 + r2

= 83.6o

Read lesson note on Refraction Of Light Through At Plane And Curved (JAMB)

Refraction Of Light Through At Plane And Curved

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